54=64x-16x^2

Solution for 54=64x-16x^2 equation:

54=64x-16x^2

We move all terms to the left:

54-(64x-16x^2)=0

We get rid of parentheses

16x^2-64x+54=0

a = 16; b = -64; c = +54;
Δ = b2-4ac
Δ = -642-4·16·54
Δ = 640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{640}=\sqrt{64*10}=\sqrt{64}*\sqrt{10}=8\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-8\sqrt{10}}{2*16}=\frac{64-8\sqrt{10}}{32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+8\sqrt{10}}{2*16}=\frac{64+8\sqrt{10}}{32}
$